2x-16x^-1/2=0

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Solution for 2x-16x^-1/2=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x-((16*x^-1)/2) = 0

2*x-8*x^-1 = 0

2*x^1-8*x^-1 = 0

(2*x^2-8*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-8*x^0) = 0

x^1

2*x^2-8 = 0

2*x^2-8 = 0

DELTA = 0^2-(-8*2*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)+0)/(2*2) or x = (0-64^(1/2))/(2*2)

x = 2 or x = -2

x in { -2, 2} 

x in { -2, 2 }

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